San Diego hospital announces birth of world’s tiniest surviving baby

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SAN DIEGO, Ca. (FOX) — A San Diego hospital on Wednesday announced the birth of what’s thought to be the world’s tiniest surviving baby, who weighed just 8.6 ounces and was smaller than an apple.

Baby Saybie — a name used by her care team — was born in December 2018 and discharged this month from the Sharp Mary Birch Hospital for Women & Newborns as a healthy five-pound infant, the hospital said in a news release. She is believed to be the world’s smallest surviving newborn, according to the Tiniest Babies Registry, which is maintained at the University of Iowa.

Her mother gave birth via emergency cesarean section at 23 weeks’ gestation. She weighed seven grams less than the previous smallest surviving newborn, who was born in Germany in 2015, according to the hospital.

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